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Berg dilemma help needed


Handwired
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I know you guys are going to say it's down to personal taste, it's what works best for the band and the type of music I play (Classic Rock) but I'm after a different angle because I only want to keep one, and trying to choose one is blowing my mind, they both sound great but with subtle differences, so musically they both nail it.
What can you come up with?

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[quote name='LukeFRC' timestamp='1401550671' post='2464670']
6x10 = 6*π*(25.4cm[sup]2[/sup]) = 12161cm[sup]2 [/sup]area

4x12 = 4*π*(30.48cm[sup]2[/sup]) = 11675cm[sup]2[/sup] area

therefore mathematically.... keep them both? :D
[/quote]Are those calculations taking in the excursion?

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[quote name='Handwired' timestamp='1401551809' post='2464685']
Are those calculations taking in the excursion?
[/quote] nope - didn't have that kinda data (hey I did your sums for you!) - hence my advice to keep them both!

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What a terrible predicament, I feel your pain. Doesn't matter which one you keep. Either way you'll have a great cab and either way you'll always wonder "should I have kept the other". Both are equally good and the difference is negligible and as you say you don't prefer one over the other then just pick one and sell it.

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Ok... I'd keep the 610, all things being equal.

I think the 610 will have the better amount of controlled bass and the ability to be a bit snappier
up top, which I would like and want... but then I would also want a horn.

My current default BEST rig is a 212 with a 210 on top and that is the best of all worlds and I think the
610 has a better chance of emulating that sort of sound and attack than a 412.

I think a 212 and therefore a 412 have potential to be great cabs in their own right but the 810 is still the ultimate
and for my needs a 610 would probably win out...but I don't say that from a point of view of owning and hearing
your cabs.

Stick with sell which ever gets the interest, then..?? :lol:

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[quote name='LukeFRC' timestamp='1401550671' post='2464670']
6x10 = 6*π*(25.4cm[sup]2[/sup]) = 12161cm[sup]2 [/sup]area

4x12 = 4*π*(30.48cm[sup]2[/sup]) = 11675cm[sup]2[/sup] area

[/quote]

When you put it like that it's obvious really...

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