Bass Of Spades Posted Friday at 15:29 Posted Friday at 15:29 So, I have managed to get myself in an Ohm quandary - I have a 2x10 cab rated 8 ohms, and a 2x15 cab rated 4 ohms... I have been running the amp through each cab individually, but fancy seeing what I get if I were to run through both. Knowing very little about Ohms, I thought I better ask the question. Can I run both cabs from the amp, and if so, what output do I run the amp at (would this be 2 Ohms?) Also, do I run an output to each cab individually (using both outputs from the amp) or do I link the cabs together using one output from the amp - just want to ask you good folk before I blow up my amp, speakers, or indeed both... Quote
fretmeister Posted Friday at 16:37 Posted Friday at 16:37 Why do people post this sort of question without saying what the amp is? Quote
Bass Of Spades Posted Friday at 16:49 Author Posted Friday at 16:49 People? This person simply didn’t realise it was important... Mesa TT 800, it has a switchable output 8, 4, or 2 ohms... 1 Quote
JJMotown Posted Friday at 17:37 Posted Friday at 17:37 Why don't people post this sort of question in the Amps & Cabs section, where they talk ohms? Quote
fretmeister Posted Friday at 18:29 Posted Friday at 18:29 1 hour ago, Bass Of Spades said: People? This person simply didn’t realise it was important... Mesa TT 800, it has a switchable output 8, 4, or 2 ohms... That would give you 2.67ohms so set the amp to 2 ohms. 2 cables from the amp or daisy chaining will be fine. Quote
neepheid Posted Friday at 19:04 Posted Friday at 19:04 Going forward, so you can work it out for yourself in future without the danger of subjecting yourself to snippy comments - adding impedances together in parallel works like this: So in your case: 1/R = 1/8 + 1/4 1/R = 3/8 R = 8/3 = 2.67 ohms 1 Quote
Bass Of Spades Posted Friday at 19:29 Author Posted Friday at 19:29 @fretmeister and @neepheid really appreciate your help - I know its probably a basic question but when you dont know you dont know. Appreciate your time in helping out. cheers 5 Quote
bremen Posted Sunday at 20:08 Posted Sunday at 20:08 On 28/03/2025 at 19:04, neepheid said: Going forward, so you can work it out for yourself in future without the danger of subjecting yourself to snippy comments - adding impedances together in parallel works like this: So in your case: 1/R = 1/8 + 1/4 1/R = 3/8 R = 8/3 = 2.67 ohms Or if you're as lazy a sod as I am: https://www.allaboutcircuits.com/tools/parallel-resistance-calculator/ 1 Quote
Suburban Man Posted Sunday at 22:07 Posted Sunday at 22:07 You may have already discovered that you will get twice the power going into the 4 ohm cab as you get going into the 8 ohm cab. Sonically quite interesting since it’s the 15” speakers that will be working hardest. Quote
bremen Posted Sunday at 22:32 Posted Sunday at 22:32 True, but the 8 ohm cab only needs to be 3dB more efficient than the 4 and they'll both be equally loud. And they'll have response variations that might result in better, maybe worse sound. Quote
Suburban Man Posted yesterday at 03:51 Posted yesterday at 03:51 5 hours ago, bremen said: True, but the 8 ohm cab only needs to be 3dB more efficient than the 4 and they'll both be equally loud. And they'll have response variations that might result in better, maybe worse sound. Agreed. I was probably being a little too oblique when I said “sonically interesting“ 🤔 Quote
prowla Posted yesterday at 06:08 Posted yesterday at 06:08 On 28/03/2025 at 17:37, JJMotown said: Why don't people post this sort of question in the Amps & Cabs section, where they talk ohms? Why don't people write Ohms correctly? 🙂 Quote
Bass Of Spades Posted yesterday at 10:30 Author Posted yesterday at 10:30 At least the sun us out... Quote
prowla Posted yesterday at 12:01 Posted yesterday at 12:01 1 hour ago, Bass Of Spades said: At least the sun us out... ...doo do doo-do. Quote
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