Commando Jack Posted November 30, 2009 Share Posted November 30, 2009 Mods please move this if this is not the place for this topic. NOOB QUESTION ALERT As I understand it, most cabs have a second connector for daisy chaining down to a second cab, usually bringing the impedence down to 4 ohms with two 8 ohm cabs, pulling the maximum power from the amp (assuming minimum load is 4 ohms). Now is there anything wrong with wiring an 8 ohm resistor (or something with an impedence of 8 ohms) across a speakon/jack plug and plugging it into the extension socket of the first cab instead? Assuming that the cab could take the extra power, surely that would mean that the rig would be running at higher power/more volume without the need for an extra cab? I am pretty sure there is a flaw in the logic somewhere. Specifically I'm thinking that while the impedence changes, the extra energy will just go to the (very hot) resistor, rather than going into sound energy. Or if the voltage remains the same by the time the current has evened out? I'm sure an expert is lurking about ready to set me straight! Quote Link to comment Share on other sites More sharing options...
Stylon Pilson Posted November 30, 2009 Share Posted November 30, 2009 (edited) [quote name='Commando Jack' post='669830' date='Nov 30 2009, 10:40 AM']Specifically I'm thinking that while the impedence changes, the extra energy will just go to the (very hot) resistor, rather than going into sound energy.[/quote] Exactly. S.P. Edited November 30, 2009 by Stylon Pilson Quote Link to comment Share on other sites More sharing options...
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